If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5x^2-12=68
We move all terms to the left:
5x^2-12-(68)=0
We add all the numbers together, and all the variables
5x^2-80=0
a = 5; b = 0; c = -80;
Δ = b2-4ac
Δ = 02-4·5·(-80)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40}{2*5}=\frac{-40}{10} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40}{2*5}=\frac{40}{10} =4 $
| 8x+25-6=35 | | 1.05)^x=1.25 | | f(0)=3-2(0 | | (6x+15)°+63+90=180 | | 176=8(6-2b) | | 3x-17=2x-8 | | -6-3x-x=-14 | | 5^(2t-4)=4 | | 1/2(2x+3/4)-1/3(1/10+x)=1 | | -3(n+5)+-3=6 | | 4k+10=-86 | | 9+2y-2=7y+2 | | −x+4=−9x+6 | | 11=2x+5-6 | | 11=2x+5-6 | | -x+4=−9x+6 | | 1+45x-23x=135 | | 7(3j-1)=15 | | 3x+8=—10 | | 5x-6/3x+2=2/3 | | 10v=2v+32 | | 1(-4y+4)=24 | | 160+36x+2x^2=2x | | |8-2x|=6+3x | | 18=-5k+4-1 | | 3t^2+2t-8=3 | | 4(d+20)=-20 | | p+6p=21 | | 5(x-0)=15 | | .7xX=9 | | 2{3x+5}=22 | | 20=-3r-r |